Factorise a2-b2-c2+2bc
WebOct 20, 2012 · ( a + b + c)2 - (a - b - c)2 + 4b2 - 4c2 = a2 + b2 + c2 + 2ab + 2bc + 2ac - ( a2 + b2 + c2 - 2ab - 2bc - 2ac) + 4b2 - 4c2 = a2 + b2 + c2 + 2ab + 2bc + 2ac - a2 - b2 - c2 + 2ab + 2bc + 2ac +4b2 - 4c2 = 4ab + 4bc + 4ac + 4b2 - 4c2 =4 ( ab + bc + ac + b2 - c2 ) ANSWER = 4 ( ab + bc + ac + b2 - c2 ) Was this answer helpful? 4 View Full Answer Web= a 2 - (b 2 - 2bc + c 2) Using identity a 2 - 2ab + b 2 = (a - b) 2 = a 2 - (b - c) 2. Using identity a 2 - b 2 = (a + b)(a - b) = (a + b - c)(a - (b - c)) = (a + b - c)(a - b + c) ∴ a 2 - b 2 …
Factorise a2-b2-c2+2bc
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WebIf a+ b+ c = 0 and a2 + b2 + c2 = ab +bc +ac, then it follows that 0 = (a+ b+ c)2 = a2 +b2 +c2 +2(ab+ bc +ac), or a2 +b2 +c2 = −2(ab +bc +ac). Put this together and we will see … WebGiven : a 2−b 2+2bc−c 2We can write it asa 2−b 2+2bc−c 2=a 2−(b 2−2bc+c 2)We know that, (a−b) 2=a 2−2ab+b 2a 2−(b 2−2bc+c 2)=a 2−(b−c) 2Based on the identity, a 2−b …
WebMar 6, 2024 · answered Factorize: b2+c2+2bc-a2 See answers Advertisement hemalathachalavadi Answer: (b+c-a) (b+c+a) Step-by-step explanation: [b^2+2bc+c^2]-a^2 (b+c)^2-a^2 (b+c-a) (b+c+a) Advertisement aniket134 (c+b)^2-a^2 (c+b+a) (c+b-a) Advertisement New questions in Math A bag contains seven tiles labeled , , , , , , and . … WebSep 20, 2016 · Factorise-a2-b2+2bc-c2 - 761991. Given : The algebraic expression is, a²-b²+2bc-c² To find : The factorisation of the given algebraic expression. Solution : We can simply solve this mathematical problem by …
Web2bc 2bc • a 2 2bc = ——— = ———————— 1 a 2 Trying to factor by pulling out : 12.2 Factoring: a 4 + 2a 3 b - 2a 2 b 2 - 4a 2 c 2 - 2ab - 2bc Thoughtfully split the expression at hand into groups, each group having two terms : Group 1: -4a 2 c 2 + a 4 Group 2: 2a 3 b - 2a 2 b 2 Group 3: -2ab - 2bc Web2ab-a2-b2-c2 Final result : -a2 + 2ab - b2 - c2 Step by step solution : Step 1 : Step 2 :Pulling out like terms : 2.1 Pull out like factors : -a2 + 2ab - b2 - c2 = -1 • (a2 - 2ab ... (c2-5)2+5 …
WebJan 25, 2024 · a2 + b2 + c2ab-bc- ca = 0. Multiply both sides with 2, we get. 2(a2 + b2 + c2ab-bc-ca) = 0. → 2a2 + 2b2 +2c2 - 2ab - 2bc - 2ca = → a2 + a2 + b2 + b2 + c2 + c2- 2ab - 2bc2ca0 (a2 - 2ab + b2) + (b2-2bc + c2) + (c2 - 2ca + a2) = 0 (a - b)2 + (b − c)2 + (ca)2 = 0. Since the sum of squares is zero, it means each term should be zero.
Web(a+b+c)^2 identity formula expansion proof (a+b+c)2=a2+b2+c2+2ab+2bc+2ca verify example prove compute ow to factorise using the identity (a+b+c)^2=a^2+b^2+c^... nick wailes agsmWeb(1): "c2" was replaced by "c^2". 1.1 Factoring: c2-81 Theory : A difference of two perfect squares, A2 - B2 can be factored into (A+B) • (A-B) Proof : (A+B) • (A-B) = A2 - AB + BA - B2 = A2 - AB + AB - B2 = A2 - B2 Note : AB = BA is … nowell movers winchester maWebOct 10, 2016 · = 4 (b + c) (a + b – c) Step-by-step explanation: let (a+b+c)2 – (a – b – c)2+ 4b2– 4c2 = a2 + b2 + c2 + 2ab + 2bc + 2ca – (a2 + b2 + c2 – 2ab + 2bc – 2ca)+ 4b2– 4c2 = a2 + b2 + c2 + 2ab + 2bc + 2ca – a2 – b2 – c2 + 2ab – 2bc +2ca + 4b2– 4c2 = 4ab + 4ca + 4b2– 4c2 = 4 (ab + ca + b2– c2) = 4 [a (b + c) + (b2– c2)] = 4 [a (b + c) + (b + c) (b – c)] nick wakefield osteopathnowell movieWebFactorise: a^2 + b^2 +c^2 + 2ab + 2bc + 2ca About Press Copyright Contact us Creators Advertise Developers Terms Privacy Policy & Safety How YouTube works Test new … nowell mount leedsWeba2+b2+c2 Formula. The a 2 + b 2 + c 2 formula is used to find the sum of squares of three numbers without actually calculating the squares. a 2 + b 2 + c 2 formula is one of the … nick waddell insuranceWebOn the other hand, the space of solutions (a,b) to any equation of the form 0 = p (a,b)q (a,b) where p,q are degree- 1 is a union of two (usually intersecting) linear subspaces in … nick waggoner twitter